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I need help with simple date script

Discussion in 'PHP' started by Grendor, Apr 16, 2005.

0
  1. #1
    According to what date it is, it has to generate horoscope sign, season of the year(winter,spring,etc). I know this in javascript but in php I'm a rookie.
    For example if the current date is between 22.5-21.6 horoscope would be gemini and for the season would be summer(of course, the season would have to have different range of date).

    I just need a few lines of code to show me how should I approuch this, the rest would be easy.
     
    Grendor, Apr 16, 2005 IP
  2. king_cobra

    king_cobra Peon

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    #2
    post the javascript and i will convert that to php for u.
     
    king_cobra, Apr 16, 2005 IP
  3. Grendor

    Grendor Peon

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    #3
    This works but with mistakes reported, I think the include part is in the wrong place. Could you please fix it?

    <html>
    <head>
    <title>Time></title>
    </head>

    <body>
    <?php

    include('time.php');
    echo getHoroscopeSign();
    echo getSeason();


    function getHoroscopeSign($time = null)
    {
    if($time == null) $time = time();
    $h = array(20,19,21,20,21,22,23,23,23,23,22,22); //Start days of months 0-11
    $s = array('Aquarius','Pisces','Aries','Taurus','Gemini','Cancer','Leo','Virgo','Li bra','Scorpio','Sagittarius','Capricorn');

    $month = date('n',$time);
    $date = date('d',$time);

    if($date < $h[$month-1])
    {
    return $s[$month-2 == -1 ? 11 : $month-2]; //Previous sign
    }
    else
    {
    return $s[$month-1]; //Current Sign
    }
    }



    echo getHoroscopeSign() . '<br />';

    function getSeason($time = null)
    {
    if($time == null) $time = time();
    $s = array('Spring','Summer','Autumn','Winter');
    $month = date('n',$time);
    if(date('d',$time) >= 21) $month++;
    $season = floor($month / 3);
    $season--;
    return $s[$season < 0 ? 3 : $season];
    }


    ?>

    </body>
    </html>
     
    Grendor, Apr 17, 2005 IP